$A$ force vector applied on a mass is represented as $\vec{F} = 6\hat{i} - 8\hat{j} + 10\hat{k} \, N$ and it accelerates with $1 \, m/s^2$. What will be the mass of the body?

  • A
    $10\sqrt{2} \, kg$
  • B
    $2\sqrt{10} \, kg$
  • C
    $10 \, kg$
  • D
    $20 \, kg$

Explore More

Similar Questions

$A$ constant force acts on a body of mass $0.9 \,kg$ at rest for $10 \,s$. If the body moves a distance of $250 \,m$,the magnitude of the force is.........$N$

$A$ car of mass $1500 \,kg$ is moving with $20 \,ms^{-1}$ velocity. If the brakes are applied,it comes to rest in $5 \,s$. The retarding force is: (in $\,N$)

$A$ constant retarding force of $50\; N$ is applied to a body of mass $20\; kg$ moving initially with a speed of $15\; m/s$. How long (in $sec$) does the body take to stop?

$A$ spherical body of mass $2\,kg$ starting from rest acquires a kinetic energy of $10000\,J$ at the end of $5^{\text{th}}$ second. The force acting on the body is $.....N$.

The position vector of a particle related to time $t$ is given by $\overrightarrow{r} = (10t \hat{i} + 15t^2 \hat{j} + 7 \hat{k}) \text{ m}$. The direction of the net force experienced by the particle is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo